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Question

Two blocks are connected over a massless pulley as shown in the figure. The mass of block A is 10 kg. If block A slides down the inclined plane at constant speed, then mass of block B in kg is


A
4
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B
3
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C
2
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D
5
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Solution

The correct option is D 5
Given,
Block A slides down with constant speed
Acceleration of block A= Acceleration of Block B=0

From FBD of block B,
T=mBg ......(i)


From FBD of block A,
T=mAgsin30
T=10×10×0.5 N=50 N

From eq (i), we get
T=mB g
50=mB g
mB=50/g=5 kg

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