Two blocks are connected with string as given in the diagram. If system is released from rest, then tension T in the string will be (All strings and pulleys are ideal).
A
12g
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B
4g
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C
2g
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D
6g
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Solution
The correct option is D 2g from the given diagram,
let, the acceleration of block 2kg is a as the length of string remain constant acceleration of 4kg block will 2 a
for 2kg block
29=2g−T−(1)
on 2a=20−T
for 4kg block
4×2a=2T−4g−(2)
(1)\div(2) 12=29−TT−2g or T−2g=4g−2T on T=2g option −C