Two blocks are in contact on a frictionless table one has a mass m and the other 2 m as shown in figure. Force F is applied on mass 2m then system moves towards right. Now the same force F is applied on m. The ratio of force of contact between the two blocks will be in the two cases respectively.

1 : 1

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1 : 2

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1 : 3

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1 : 4

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Solution

The correct option is B
1 : 2

When the force is applied on mass 2m contact force $f_{1} = \frac{m}{m + 2 m} g = \frac{g}{3}$

When the force is applied on mass m contact force $f_{2} = \frac{2 m}{m + 2 m} g = \frac{2}{3} g$

Ratio of contact forces $\frac{f_{1}}{f_{2}} = \frac{1}{2}$

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Two blocks are in contact on a frictionless table masses $2 m$ and $m$ respectively as shown in figure. Force F is applied on mass $2 m$ then system moves towards right. Now the same force F is applied on $m$ . The ratio of force of contact between the two blocks will be in the two cases respectively.

Two blocks are in contact on a frictionless table. One has mass m and the other 2 m. A force F is applied on 2 m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of the force of contact between the two blocks will be :