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Question

Two blocks each having a mass M are placed as shown in the figure. The acceleration of the system is:

280654_1cc5b0c9d1e64e9ebf5b404f24d94ef6.png

A
0
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B
gsinθ2
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C
gsinθ
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D
2gsinθ
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Solution

The correct option is C gsinθ2
Let common acceleration of the system is a
FBD of mass m inclined at an angle θ
mgsinθT=ma...(1)
and FBD of block lying on surface
T=ma...(2)
from (1) and (2) mgsinθ=2maa=g2sinθ
256053_280654_ans.png

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