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Question

Two blocks m1 and m2 are resting on a rough inclined plane of inclination 37 as shown in figure. The contact force between the blocks is, (m1=4 kg,m2=2 kg,μ1=0.8,μ2=0.5,g=10 m/s2,sin37=3/5)

A
3.2 N
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B
3.6 N
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C
7.2 N
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D
Zero
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Solution

The correct option is D Zero
For a mass sliding down
writting the Newton's law equation on the block we get
mgsinθf=ma
Where f is the friction force
f=μmgcosθ
a=gsinθμgcosθ
Here the acceleration of blocks depends on the μ as μ1>μ2
a1<a2
m2 slips before m1

So, no contact between m1 and m2
N=0

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