Two blocks of equal masses M are connected by a string and are kept on a rough horizontal surface as shown in the figure. μ is the coefficient of friction between the blocks and the surface. If 0<F1−F2<2μMg , then choose the correct statement.
A
The direction of friction on block A is towards right.
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B
The direction of friction on block B is either towards left or right
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C
Tension in the string is zero
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D
Friction force on block B is zero
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Solution
The correct option is B The direction of friction on block B is either towards left or right Since, it is given that 0<F1−F2<2μMg ⇒F1>F2
So, block A is the driving block and block B is driven block.
Maximum opposing force on the blocks =μ(M+M)g=2μMg
As F1–F2<2μMg, so system will not accelerate.
Hence, friction on block A acts towards left but in the block B it may act left or right.