Two blocks of mass 1kg and 2kg are connected by string AB of mass 1kg. The blocks are placed on a smooth horizontal surface. Block of mass 1kg is pulled by a horizontal force F of magnitude 8N. Find the tension in the string at points A and B.
A
4N,6N
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B
3N,5N
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C
3N,4N
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D
5N,6N
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Solution
The correct option is D4N,6N
The total mass of the system is m=2+1+1=4kg
Let a be the acceleration of the system.
Thus, ma=F or 4a=8 or a=2m/s2
The tension at A is TA= mass of left block × acceleration =2×2=4N
and tension at B is TB= (mass of left block + mass of string AB)× acceleration =(2+1)×2=6N