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Question

Two blocks of mass 2 kg and 4 kg are kept in contact with each other on a smooth horizontal surface. A horizontal force of 12 N is applied on the first block due to which they move with certain constant acceleration. Calculate the force between the blocks.


A

2 N

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B

4 N

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C

8 N

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D

16 N

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Solution

The correct option is C

8 N



Let a be the common acceleration of blocks.
R = Force between the two blocks
From FBD of block 1
F - R = m1a . . . (i)

From FBD of block 2,
R = m2 a . . . (ii)
From (i) & (ii), F=(m1+m2)a
a=Fm1+m2=126=2m/sec2
Force between blocks a=(4×2)N=8N


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