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Question

# Two blocks of mass 2 kg and 4 kg are kept in contact with each other on a smooth horizontal surface. A horizontal force of 12 N is applied on the first block due to which they move with certain constant acceleration. Calculate the force between the blocks.

A

2 N

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B

4 N

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C

8 N

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D

16 N

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Solution

## The correct option is C 8 N Let a be the common acceleration of blocks. R = Force between the two blocks From FBD of block 1 F - R = m1a . . . (i) From FBD of block 2, R = m2 a . . . (ii) ∴ From (i) & (ii), F=(m1+m2)a ∴ a=Fm1+m2=126=2m/sec2 ∴ Force between blocks a=(4×2)N=8N

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