Two blocks of mass 4 kg 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be:

2 N

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4 N

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3 N

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None of the above

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Solution

The correct option is C 2 N
Given that,

Mass $m_{1} = 6 k g$

Mass $m_{2} = 4 k g$

Force $F = 5 N$

Now, the acceleration is

$F = (m_{1} + m_{2}) a$

$a = \frac{F}{(m_{1} + m_{2})}$

$a = \frac{5}{4 + 6}$

$a = 0.5 m / s^{2}$

Now, force on lighter mass

$F = m_{2} \times a$

$F = 4 \times 0.5$

$F = 2 N$

Hence, the force is $2 N$

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