$T w o b l o c k s o f m a s s 4 k g a n d 2 k g a r e p l a c e d s i d e b y s i d e o n a s m o o t h h o r i z o n t a l s u r f a c e a s s h o w n i n t h e f i g u r e . A h o r i z o n t a l f o r c e o f 20 N i s a p p l i e d o n 4 k g b l o c k . F i n d t h e a c c e l e r a t i o n o f e a c h b l o c k .$

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Solution

The correct option is D

$S i n c e, b o t h t h e b l o c k s w i l l m o v e w i t h s a m e a c c e l e r t i o n (s a y a) i n h o r i z o n t a l d i r e c t i o n . L e t u s t a k e b o t h t h e b l o c k s a s a s y s t e m . N e t e x t e r n a l f o r c e o n t h e s y s t e m i s 20 N i n h o r i z o n t a l d i r e c t i o n . U s i n g \sum F_{x} = m a_{x} 20 = (4 + 2) a = 6 a a = \frac{10}{3} m / s^{2}$

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Two blocks of mass 4 kg and 2 kg are placed side by side on a smooth horizontal surface as shown in the figure.A horizontal force of 20 N is applied on 4 kg block.Find the acceleration of each block.

The correct option is D Since, both the blocks will move with same accelertion (say a) in horizontal direction.Let us take both the blocks as a system. Net external force on the system is 20 N in horizontal direction.Using∑Fx=max20=(4+2)a=6aa=103 m/s2