Two blocks of mass 5kg and 3kg are tied with a heavy rope of mass 2kg. An external force of 200N is applied on 5kg block and the whole system accelerates upwards. Find the tension at the midpoint of the rope?
(Take g=10m/s2)
A
80N
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B
100N
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C
120N
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D
60N
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Solution
The correct option is A80N To calculate the total acceleration let us consider the entire setup to be a system of mass (5+2+3)=10kg
FBD of the system will be
Using FBD, we can write F−Mg=Ma 200−10×10=10×a a=10m/s2
The rope of mass 2kg can be seen to be made up of two parts of 1kg each, of equal length.
Now, the FBD of the lower part of the system will be
Using FBD, we can write T−4×g=4×a T−4×10=4×10 ⟹T=80N