Two blocks of mass m each is connected with the string which passes over fixed pulleys, as shown in figure. The force exerted by the string on the pulley P is :

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2mg

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\sqrt{2} m g

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4mg

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Solution

The correct option is A mg
$\begin{matrix} F = 2 T cos 60^{0} = T = m g \end{matrix}$
$∴$ Option $A$ is correct.

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Two blocks of mass m each is connected with the string which passes over fixed pulleys, as shown in figure. The force exerted by the string on the pulley P is :

The correct option is A mgF=2Tcos600=T=mg∴ Option A is correct.

The correct option is A mg
$\begin{matrix} F = 2 T cos 60^{0} = T = m g \end{matrix}$
$∴$ Option $A$ is correct.