Question

Two blocks of masses $1kg$ and $2kg$ are placed in contact on smooth horizontal surface as shown in $Figs.6.34$ and $6.35$. A horizontal (a) on a $1kg$ block (b) a $2kg$ block. Find the force of interaction of the blocks.

Answer 1

Since both the blocks are in contact, therefore, they will move together with an acceleration
$a=\frac{F_{net}}{M_{total}}=\frac{6}{2+1}=2m{s}^{-2}$

Let the force of interaction between them is $R_1$ By Newton's second law for $2kg$ block, Normal reaction on $2kg$ block, $R_1=2a=2\times 2=4N$

Let the force of interaction between them is $R_2$ By Newton's second law for $1kg$ block, normal reaction on $2kg$ block, $R_2=1a=1\times 1=1N$