Question

Two blocks of masses 10 kg and 20 kg are connected by a massless string and are placed on a smooth horizontal surface as shown in the figure. If a force F = 600 N is applied to 10 kg block, then the tension in the string is:

• A. 100 N
• B. 200 N
• C. 300 N
• D. 400 N

Answer 1

The correct option is D 400 N

Here, $m_1=10kg,m_2=20kg,F=600N$
Let T be tension of the string and a be common acceleration of the system.
$\therefore a=\frac{F}{m_1+m_2}=\frac{600N}{10kg+20kg}=\frac{600}{30}m{s}^{-2}=20m{s}^{-2}$

When a force F is applied on 10 kg block, then the tension in the string is
$T=m_{2}a=\left(20kg\right)\left(20m{s}^{-2}\right)=400N$