Two blocks of masses 10Kg each are placed over each other as shown in the figure. A force of 50N is exerted on the top block. The coefficient of friction μ between the blocks is 0.5. Find the acceleration of the two blocks.
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Solution
Let assume both blocks are moving with different acceleration,
a1 = acceleration of block A
a2= acceleration block B,
From FBD of Block A,
F−f=ma1, ......1
f=μN, N=mg, ⇒f=μmg= .5×10×10= 50,
Using value of f in equation 1,
⇒a1=0 , So our assumption is wrong.
We take both block as system, let acceleration is a,