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Question

Two blocks of masses 2.9 kg and 1.9 kg are suspended from a rigid support by two inextensible wires each of length 1 m, the upper wire has negligible mass and the lower wire has a uniform mass of 0.2 kg/m. The whole system of block, wire and support has an upward acceleration of 0.2 m/s2.
The tension at the mid-point of lower wire is:

A
10.4 N
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B
20.4 N
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C
20 N
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D
30 N
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Solution

The correct option is C 20 N
Total mass of lower wire, mw=0.2×1=0.2 kg
Since the wire is uniform, therefore mass of the half wire length will also be half i.e. 0.1 kg
Considering FBD consisting of half of lower wire and lower block,
Using Newton's second law,
T2g=2(0.2)
T=19.6+0.4=20 N

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