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Standard XII

Physics

Displacement of COM:Application

Two blocks of...

Question

Two blocks of masses $2 k g$ and $4 k g$ are connected by a light string and kept on horizontal surface. A force of $16 N$ is acted on $4 k g$ block horizontally as shown in figure. Besides it is given that coefficient of friction between $4 k g$ and ground is $0.3$ and between $2 k g$ block and ground is $0.6$ . Then frictional force between $2 k$ g block and ground is:

12 N

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6 N

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4 N

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Solution

The correct option is C $4 N$
As shown in figure above
If we balance forces on $4 k g$ bolck the value of $T$ comes out to be $4 N$
$F_{s} = 12 N$ in case of $4 k g$ block
Now on balancing the forces on $2 k g$ block, $F_{s}$ = $T$
Therefore $F_{s} = 4 N$ .

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Two blocks of mass 4 kg and 2 kg are connected by a heavy string and placed on rough horizontal plane. The 2 kg block is pulled with a constant force to the right. The coefficient of friction between the blocks and the ground is 0.4. What is the value of so that tension in the string is constant throughout during the motion of the blocks: $(g = 10 m / s^{2})$

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The correct option is C 4NAs shown in figure above If we balance forces on 4kg bolck the value of T comes out to be 4N Fs=12N in case of 4kg blockNow on balancing the forces on 2kg block, Fs =TTherefore Fs=4N.

The correct option is C $4 N$
As shown in figure above
If we balance forces on $4 k g$ bolck the value of $T$ comes out to be $4 N$
$F_{s} = 12 N$ in case of $4 k g$ block
Now on balancing the forces on $2 k g$ block, $F_{s}$ = $T$
Therefore $F_{s} = 4 N$ .