Two blocks of masses 2kg and 5kg are at rest on the ground. The masses are connected by a string passing over a frictionless pulley which is under the influence of a constant upward force F=50N. The acceleration of 5kg and 2kg masses are
A
0,2.5ms−2
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B
0,0
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C
2.5ms−2,2.5ms−2
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D
1ms−2,2.5ms−2
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Solution
The correct option is A0,2.5ms−2 FBD of Individual bodies ⇒2T=50N T=25N Total force downward due to 2kg is 20N as T>20N,2kg mass will leave the ground FnetT−20=2a ⇒a=2.5m/s2 Total force downward due to 5kg is 50N as T<505kg mass will be at rest on ground a5=0