Two blocks of masses 2kg and 5kg are at rest on the ground. The masses are connected by a string passing over a frictionless pulley which is under the influence of a constant upward force F=50kgm/s2. The accelerations of 5kg and 2kg masses are :
A
0,2.5ms−2
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B
0,0
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C
2.5ms−2,2.5ms−2
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D
1ms−2,2.5ms−2
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Solution
The correct option is A0,2.5ms−2 Here the masses will be lifted if the tension in the sting is greater than the gravitational pull of the masses. Weight of 2kg mass =2g=20N Weight of 5kg mass =5g=50N From FBD, 2T=50⇒T=25N As the weight of 5kg mass is less than the tension. so it can not lift and its acceleration is zero. Now for 2kg mass, 2a=25−20=5⇒a=2.5m/s2