Two blocks of masses 3 kg and 2 kg are tied to two ends of an inextensible string which passes over a frictionless pulley. The tension in the string between ceiling and the axle of pulley is
From the FBDs of blocks
m1g−T=m1a ...(i)
T−m2g=m2a ...(ii)
Solving these two equations for tension T
T=2m1m2m1+m2g=2×2×3×102+3=24 N
Now, 2T=2×24=48 N