wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two blocks of masses 3 kgand 6 kg respectively are placed on a smooth horizontal surface. They are connected by a light spring of force constant k=200N/m. Initially the spring is unstretched. The indicated velocities are imparted to the blocks. Find the maximum extension of the spring.

A
30 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
60 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
90 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 30 cm
Here reduced mass μ=6×36+3=2 kg

Initial kinetic energy of system w.r.t CM
(Ki)cm=12mM(m+M)V2rel=(2(1))2=9 J

At maximum extension Vrel=0

Final kinetic energy of system w.r.t CM
(Kf)cm=0

Now, using WE theorem in COM frame
Ki+Ui=Kf+Ut
9+0=0+12Kx2
9=100x2
x=0.3 m=30 cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon