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Question

# Two blocks of masses 4 kg and 10 kg are connected by a flexible inextensible string as shown in given figure. The pulley is assumed to be light and frictionless. The coefficient of friction between the 4 kg block and the suface is 0.2 (μs=μk=0.2). The angle of inclination of the plane is 30∘. Assuming the sytem to be released from rest, the acceleration of 10 kg block is (g=10 ms−2)

A
5.2 ms2
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B
6.6 ms2
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C
41.8 ms2
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D
13 ms2
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Solution

## The correct option is A 5.2 ms−2In the scenario presented in the question, 4 kg block slides up on the surface of inclined plane. So, friction acting will be kinetic in nature and acts downwards along the incline i.e f=fk=μkNcosθ=((0.2)4gcos30∘ acceleration of system: a=Fnetm solving for which get following: a=(10g−4gsin30∘−(0.2)(4)gcos30∘10+4) ⇒a=(10−2−0.7)14g ⇒a=(7.314)10 ⇒a=5.2 ms−2 Hence, the nearest correct answer is (A).

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