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Question

Two blocks (of masses 400kg and 30kg) are attached to the two ends of a string passing over a smooth pulley as shown in the figure. The tension in the string will be :

134641_347443997df447a49e0749dea0fd5512.png

A
400N
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B
850N
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C
1000N
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D
2000N
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Solution

The correct option is A 400N
For 400kg block, 400a=400gsin37T.....(1)

for 30kg block, 30a=T30gsin53......(2)

Adding (1) and (2)

(400+30)a=(400sin3730sin53)g=2400240

As, (sin3735,sin5345,g=10)

So, a=2160430=5m/s2

Now using (1),

The tension, T=400gsin37400a=24002000=400N

152150_134641_ans_d24d63db77a94d30a395bf3d491d234c.png

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