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Normal Force

Two blocks of...

Question

Two blocks of masses 5 kg and 10 kg are connected by a massless spring. A force of 20 N acts on 10 kg mass as shown. At the instant, 5 kg mass has an acceleration of 0.4 $m s^{- 2}$ the acceleration of 10 kg mass is

A

2.9 ms^-2

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B

1.8 ms^-2

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C

3.5 ms^-2

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D

1 ms^-2

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Solution

The correct option is B
1.8 ms^-2

$let the spring force at that instant is F_{s p} F B D o f 5 k g F_{s p} = 5 a_{1} . . . . . . . . . . [∴ F_{n e t} = m a] = 5 \times 0.4 = 2 N F B D o f 10 k g F_{s p} = 20 - F_{s p} = 20 - 2 = 18 N A s F_{s p} = m a, 18 = 10 a_{2} \Rightarrow a_{2} 1.8 m s^{- 2} ∴ A c c e l e r a t i o n o f 10 k g m a s s a t t h e i n s t a n t g i v e n i s 1.8 m s^{- 2}$

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