Two blocks of masses 5 kg and 10 kg are connected by a massless spring. A force of 20 N acts on 10 kg mass as shown. At the instant, 5 kg mass has an acceleration of 0.4 ms−2 the acceleration of 10 kg mass is
1.8 ms-2
let the spring force at that instant isFspFBD of 5kgFsp=5a1..........[∴Fnet=ma]=5×0.4=2NFBD of 10 kgFsp=20−Fsp=20−2=18NAsFsp=ma,18=10a2⇒a2 1.8ms−2∴Acceleration of 10kg mass at the instant given is 1.8ms−2