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Question

# Two blocks of masses 5 kg and 2 kg are connected by a massless string as shown in figure. A vertical force F is applied on the 5 kg block. Find the value of F if tension in the string is 40 N. (g=10 m/s2)

A
140 N
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B
70 N
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C
40 N
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D
100 N
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Solution

## The correct option is A 140 NBy the free body diagram, It is given that the tention in the string is T=40 N, we also know that the whole system will move with acceleration a . By the free body diagram of the individual block, For 2 kg block Writing the force equation T−20=2×a⇒40−20=2×a a=10 m/s2 By the free body diagram of 5 kg and the acceleration is same as a=10 m/s2 Writing the force equation F−T−50=5a, F−40−50=5×10, on solving F=140 N Hence option (a) is the correct answer.

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