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Question

# Two blocks of masses 6 kg and 4 kg are attached to the two ends of a massless string passing over a smooth fixed pulley. If the system is released, the acceleration of the centre of mass of the system will be :

A
g, vertical downwards
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B
g/5, vertical downwards
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C
g/25, vertical downwards
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D
zero
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Solution

## The correct option is C g/25, vertical downwardsbasic formula for atwood machine : acceleration of masses =(m1−m2)gm1+m2=(6−4)g6+4=0.2g6kg masses is going down and 4kg will go up ,hence acceleration of 4kg can be taken as -ve. so acceleration of COM=m1a1+m2a2m1+m2=(6−4)0.2g6+4=0.04g

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