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Question

Two blocks of masses 8kg are connected by a spring of negligible mass and placed on a frictions less horizontal surface. An impulse gives a velocity of 12m/s to the heavier block in the direction of lighter block. The velocity of the center of mass is:-

A
12m/s
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B
10m/s
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C
8m/s
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D
6m/s
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Solution

The correct option is D 6m/s
Velocity of center of mass is =m1v1+m2v2m1+m2

=8×12+8×08+8

=96+016

=6m/s
Hence, the answer is 6m/s.


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