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Question

Two blocks of masses m1=1 kg and m2=2 kg are connected by massless strings and placed on a horizontal frictionless surface as shown in figure. A force F=12 N is applied to mass m1 as shown then tension (T) between m1 and m2
1360391_deb3ef8c82b74c3ea0ed571f2ce3eec2.png

A
4 N
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B
8 N
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C
10 N
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D
2 N
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Solution

The correct option is B 8 N
Net force on the system(m1+m2=3kg) is F=12N so the common acceleration will be a=F3kg=4m/s2
When we consider m2 we notice that only horizontal force on it is T so it should produce
an acceleration 4m/s2 in m2 so that it can move together with m1 so 4m/s2=Tm2
ot T=4m/s2×2kg=8N

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