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Standard XII

Physics

Net Contact Force

Two blocks of...

Question

Two blocks of masses $m_{1} = 5 k g$ and $m_{2} = 6 k g$ are connected by a light string passing over a light frictionless pulley as shown. The mass $m_{1}$ is at rest on the inclined plane and mass $m_{2}$ hangs vertically. If the angle of incline $θ = 30^{0}$ what is magnitude and direction of force of friction on the 5kg block
$(g = 10 m s^{- 2})$

35 N up the plane

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35 N down the plane

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85 N up the plane

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85 N down the plane

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Solution

The correct option is B 35 N down the plane
$m_{2} = 6 k g$
$T = 6 \times 10 = 60 N$
Force along plane, $F_{1} = m g sin θ = 25 N$
Balancing forces along the plane;
$∴ T - m g s i n 30^{0} - f = 0$
$f = T - m g s i n 30^{0}$
$= 60 - 25 = 35 N$

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The correct option is B 35 N down the planem2=6kgT=6×10=60NForce along plane, F1=mgsinθ=25NBalancing forces along the plane;∴T−mgsin300−f=0f=T−mgsin300 =60−25=35 N

The correct option is B 35 N down the plane
$m_{2} = 6 k g$
$T = 6 \times 10 = 60 N$
Force along plane, $F_{1} = m g sin θ = 25 N$
Balancing forces along the plane;
$∴ T - m g s i n 30^{0} - f = 0$
$f = T - m g s i n 30^{0}$
$= 60 - 25 = 35 N$