You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Rotational EMF

Two blocks of...

Question

Two blocks of masses m and M $>$ 2m are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in figure. The system is then released.
If m $=$ 1 kg, A $=$ 8x10 $^{- 9} m^{2}$ , the breaking stress $=$ 2x10 $^{9}$ Nm $^{- 2}$ and g $=$ 10ms $^{- 2}$ , the maximum value of M for which the wire will not break is

4 kg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 4 kg
Breaking stress $= 2 \times 10^{9} \Rightarrow M a x T e n s i o n = 2 \times 10^{9} \times 8 \times 10^{- 9}$
$= 16 N$
$16 - 10 = 1. a$
$a = 6 m / s^{2}$
$M g - 16 = 6 M$
$10 M - 16 = 6 M$
$M = 4 k g$

Suggest Corrections

Similar questions

Q. Two block of masses

m

and

M

are connected by means of a metal wire passing over a frictionless fixed pulley. The area of cross-section of the wire is

6.5 \times 10^{- 9} m^{2}

and its breaking stress is

2 \times 10^{9} N m^{- 2}

. If

m = 1 k g,

if the maximum value of M is

K \times 1.86

kg for which the wire will not break. Find the value of

K

. (g = 10 m/s

^{2}

)

Q. Two blocks of masses

m

and

M

2 m

are connected by means of a metal wire of cross sectional area A, passing over a frictionless fixed pulley as shown in figure. The system is then released.
The stress produced in the wire is :

Q. Two blocks of masses m and M

=

2m are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in figure. The system is then released.
The common acceleration of the blocks is

Q. Two blocks of masses

m

and

2 m

are connected through a wire of breaking stress

S

passing over a frictionless pulley. The maximum radius of wire used so that the wire may not break is

Two blocks of masses 1 kg and 2 kg are connected by a metal wire going over a smooth pulley as shown in figure. The breaking stress of the metal is $2 \times 10^{9} N m^{- 2}$ . What should be the minimum radius of the wire used if it is not to break? Take $g = 10 m s^{- 2}$ .

Join BYJU'S Learning Program

The correct option is B 4 kgBreaking stress =2×109⇒Max Tension=2×109×8×10−9=16N16−10=1.aa=6m/s2Mg−16=6M10M−16=6MM=4kg

The correct option is B 4 kg
Breaking stress $= 2 \times 10^{9} \Rightarrow M a x T e n s i o n = 2 \times 10^{9} \times 8 \times 10^{- 9}$
$= 16 N$
$16 - 10 = 1. a$
$a = 6 m / s^{2}$
$M g - 16 = 6 M$
$10 M - 16 = 6 M$
$M = 4 k g$