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Standard XII

Physics

Rotational EMF

Two blocks of...

Question

Two blocks of masses m and M $>$ 2m are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in figure. The system is then released.
If m $=$ 1 kg, A $=$ 8x10 $^{- 9} m^{2}$ , the breaking stress $=$ 2x10 $^{9}$ Nm $^{- 2}$ and g $=$ 10ms $^{- 2}$ , the maximum value of M for which the wire will not break is

4 kg

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6 kg

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8 kg

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10 kg

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Solution

The correct option is B 4 kg
Breaking stress $= 2 \times 10^{9} \Rightarrow M a x T e n s i o n = 2 \times 10^{9} \times 8 \times 10^{- 9}$
$= 16 N$
$16 - 10 = 1. a$
$a = 6 m / s^{2}$
$M g - 16 = 6 M$
$10 M - 16 = 6 M$
$M = 4 k g$

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The correct option is B 4 kgBreaking stress =2×109⇒Max Tension=2×109×8×10−9=16N16−10=1.aa=6m/s2Mg−16=6M10M−16=6MM=4kg

The correct option is B 4 kg
Breaking stress $= 2 \times 10^{9} \Rightarrow M a x T e n s i o n = 2 \times 10^{9} \times 8 \times 10^{- 9}$
$= 16 N$
$16 - 10 = 1. a$
$a = 6 m / s^{2}$
$M g - 16 = 6 M$
$10 M - 16 = 6 M$
$M = 4 k g$