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Standard XII

Physics

Spring Block's Time Period

Two blocks of...

Question

Two blocks of masses m and M are moving with speeds $v_{1} a n d v_{2} (v_{1} > v_{2})$ in the same direction on the frictionless surface respectively, M being ahead of m. An ideal spring of force constant k is attached to the

v_{1} \sqrt{\frac{m}{k}}

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v_{2} \sqrt{\frac{m}{k}}

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(v_{1} - v_{2}) \sqrt{\frac{m M}{(M + m) K}}

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None of above is correct.

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Solution

The correct option is A $v_{1} \sqrt{\frac{m}{k}}$
$\begin{matrix} A c c o r d i n g t o q u e s t i o n : b y h o o k e^{'} s l a w, F = - K x K i n e t i c e n e r g y o f m a s s (m) m o v i n g w i t h v e l o c i t y (v_{1}) i s \frac{1}{2} m v_{1} {\sqrt{a}}^{2} a n d, i s t r a n s f e r r t o a n o t h e r m a s s (M) a n d f o r c e e x e r t e d o n : \frac{1}{2} m \frac{{v_{1}}^{^{2}}}{x} | w h e r e x = c o m p r e s s i o n i n t h d s p r i n g . N o w, u s i n g, h o o k e^{'} s l a w : v_{1} \sqrt{\frac{m}{k}} s o t h a t t h e c o r r e t o p t i o n i s A . \end{matrix}$

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