Two blocks of same mass m are connected to each other by spring of spring constant k. Initially spring is compressed by x0 and blocks are connected by string. Whole system is placed on a smooth horizontal table. Now both blocks are given same horizontal velocity v perpendicular to spring and string is cut simultaneously. During subsequent motion of blocks.
Find the speed of blocks when extension in spring is maximum
v
Motion is SHM in vertical direction with two extreme positions at maximum compression maximum elongation respectively. Using law of conservation of energy
2×12mv2+12kx20=2×12mv,2+12kx20
v'=v