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Question

Two blocks of same mass m are connected to each other by spring of spring constant k. Initially spring is compressed by x0 and blocks are connected by string. Whole system is placed on a smooth horizontal table. Now both blocks are given same horizontal velocity v perpendicular to spring and string is cut simultaneously. During subsequent motion of blocks.

Find the speed of blocks when extension in spring is maximum


A

v

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B

v2

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C

zero

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D

None of these

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Solution

The correct option is A

v


Motion is SHM in vertical direction with two extreme positions at maximum compression maximum elongation respectively. Using law of conservation of energy

2×12mv2+12kx20=2×12mv,2+12kx20

v'=v


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