You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Engineering Mechanics

Introduction to Wedges

Two blocks wi...

Question

Two blocks with the mass M and m are in contact with each other and are resting on horizontal frictionless floor. When horizontal force is applied to the heavier, the blocks accelerate to the right. The force between the two blocks are.

\frac{(M + m) F}{m}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{M F}{m}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m F}{(M + m)}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{m F}{(M + m)}$

Considering 'M' and 'm' together to be our system

$F = (M + m) a$

$a = \frac{F}{(M + m)}$

Force acting on small mass

$N = m \times a = \frac{m F}{M + m}$

$= force between two masses$

Suggest Corrections

Similar questions

Q. Two blocks of masses

2 k g

and

1 k g

are in contact with each other on a frictionless table, when a horizontal force of

3.0 N

is applied to the block of mass

2 k g

the value of the force of contact between the two blocks is:

Q. Two blocks of mass 4 kg 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be:

Two blocks of mass 2 kg and 4 kg are kept in contact with each other on a smooth horizontal surface. A horizontal force of 12 N is applied on the first block due to which they move with certain constant acceleration. Calculate the force between the blocks.

Q. Two blocks A and B of masses 10 kg and 15 kg are placed in contact with each other at rest on a rough horizontal surface as shown in the figure. The coefficient of friction between the blocks and surface is 0.2. A horizontal force of 200N is applied to block A. The acceleration of the system is
(Take g=10

m s^{- 2}

)

Q. Two blocks of mass

4 k g

and

2 k g

are placed in contact with each other on a frictionless horizontal surface. If we apply a push of

5 N

on the heavier mass, the force on the lighter mass will be

Join BYJU'S Learning Program

Two blocks with the mass M and m are in contact with each other and are resting on horizontal frictionless floor. When horizontal force is applied to the heavier, the blocks accelerate to the right. The force between the two blocks are.

The correct option is D mF(M+m) Considering 'M' and 'm' together to be our system F=(M+m)a a=F(M+m) Force acting on small mass N=m×a=mFM+m =force between two masses

The correct option is D $\frac{m F}{(M + m)}$

Considering 'M' and 'm' together to be our system

$F = (M + m) a$

$a = \frac{F}{(M + m)}$

Force acting on small mass

$N = m \times a = \frac{m F}{M + m}$

$= force between two masses$