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Question

# Two bodies 'A' and 'B' having masses M and 3M respectively are kept at a distance 'y' apart. A small particle is to be placed so that the net gravitational force on it due to A and B is zero. Its distance from mass A will be

A
x=y1+3
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B
x=y1+6
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C
x=y1+2
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D
x=y1+4
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Solution

## The correct option is A x=y1+√3Let m be the mass of the particle which is placed at a distance x from A. F1=GMmx2towards A and F2=G(3M)m(y−x)2 towards B The net force = 0, if F1=F2 ⇒GMmx2=G(3M)m(y−x)2 ⇒√3x=y−x ⇒x=y1+√3

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