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Question

Two bodies A and B of equal masses are kept at heights of h and 2h respectively. What will be the ratio of their potential energy?

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Solution

Mass of body A, m1=m
Mass of body B, m2=m
Height h1=h
Height h2=2h
Acceleration due to gravity, g1=g
Acceleration due to gravity, g2=g
PotentialEnergy(P.E1)PotentialEnergy(P.E2)=?
P.E=mgh
P.Eαh
( 'm' and 'g' are constants)
P.E1P.E2=h1h2
P.E1P.E2=h2hP.E1P.E2=12
Therefore, the ratio of potential energy is of the two bodies is 1 : 2.

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