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Question

Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and its density is 9gcm3 If the mass of the other is 48g, its density in gcm3 is
  1. 3
  2. 5


Solution

The correct option is C 3
Apparent weight V(ρσ)g=mρ(ρσ)g 
where  m = mass of the body
ρ =density of the body 
σ =density of water
If two bodies are in equilibrium then their apparent weight must be equal
m1ρ1(ρ1σ)=m2ρ2(ρ2σ)
369(91)=48ρ2(ρ21)
By solving we get ρ=3 

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