Question

Two bodies are projected from the ground with the same speed. If the angles of their projection from the ground are ${30}^{\circ }$ and ${60}^{\circ }$ respectively, what is the ratio of their horizontal displacements after $2s$?

Answer 1

$S_H=u_H\times t$
$\therefore S_1:S_2=ucos30\times 2:ucos60\times 2$

$=\frac{\sqrt{3}}{2}:\frac{1}{2}=\sqrt{3}:1$