Two bodies are projected from the top of a tower in opposite directions with velocities of u1 and u2 simultaneously. Find the time when their velocities are mutually perpendicular.
A
2√u1u2g
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B
√u1u2g
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C
√4u1u2g
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D
√8u1u2g
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Solution
The correct option is B√u1u2g
At time t,
Velocity of first body →v1=−u1^i−gt^j
Velocity of second body →v2=u2^i−gt^j
When velocities are perpendicular, →v1.→v2=0⇒−u1u2+g2t2=0⇒t=√u1u2g