Question

Two bodies are projected with the same velocity. If one is projected at an angle of ${30}^{\circ }$ and the other at an angle of ${60}^{\circ }$ to the horizontal, the ratio of the maximum heights reached is

• A. 3 :1
• B. 1 : 3
• C. 1 : 2
• D. 2 : 1

Answer 1

The correct option is B

1 : 3

As $H=\frac{u^{2}si{n}^2\theta }{2g}\therefore \frac{H_1}{H_2}=\frac{si{n}^2{\theta }_1}{sin{\theta }_2}=\frac{si{n}^2{30}^{\circ }}{si{n}^2{60}^{\circ }}=\frac{\frac{1}{4}}{\frac{3}{4}}=\frac{1}{3}$