Two bodies are thrown with the same initial speed at angles - and 90o- with the horizontal- What will be the ratio of maximum heights attained by them-

Maximum height in a projectile is #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; H= u ^ 2 sin ^ 2 α #160; #160; ...

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Standard XII

Physics

Introduction

Two bodies ar...

Question

Two bodies are thrown with the same initial speed at angles $α$ and $(90^{o} - α)$ with the horizontal. What will be the ratio of maximum heights attained by them?

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Solution

Maximum height in a projectile is
$H = \frac{u^{2} {sin}^{2} α}{2 g}$

Ratio of maximum heights

$= \frac{\frac{u^{2} {sin}^{2} α}{2 g}}{\frac{u^{2} {sin}^{2} (90 - α)}{2 g}} = {tan}^{2} α$

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Two bodies are thrown with the same initial speed at angles α and (90o−α) with the horizontal. What will be the ratio of maximum heights attained by them?

Maximum height in a projectile is H=u2sin2α2gRatio of maximum heights=u2sin2α2gu2sin2(90−α)2g=tan2α

Two bodies are thrown with the same initial speed at angles $α$ and $(90^{o} - α)$ with the horizontal. What will be the ratio of maximum heights attained by them?

Maximum height in a projectile is
$H = \frac{u^{2} {sin}^{2} α}{2 g}$

Ratio of maximum heights

$= \frac{\frac{u^{2} {sin}^{2} α}{2 g}}{\frac{u^{2} {sin}^{2} (90 - α)}{2 g}} = {tan}^{2} α$