Question

Two bodies are thrown with the same initial velocity at angles $({90}^0-\theta )$ and $\theta$ and respectively with the vertical, then their maximum heights are in the ratio

• A. 1 : 1
• B. $\sin \theta :\cos \theta$
• C. ${\sin }^2\theta :{\cos }^2\theta$
• D. $\cos \theta :\sin \theta$

Answer 1

The correct option is C ${\sin }^2\theta :{\cos }^2\theta$

Maximum heights are given as $\frac{u^{2}si{n}^2\theta }{2g}$
Thus ratio will be $si{n}^2\theta :si{n}^2(90-\theta )=si{n}^2\theta :co{s}^2\theta$