Question

Two bodies are thrown with the same initial velocity at angles $\theta$ and $({90}^{\circ }-\theta )$ respectively with the horizontal, then their maximum heights are in the ratio:

• A. 1:1
• B.
• C.
• D.

Answer 1

The correct option is C

We know that
$H=\frac{u^{2}si{n}^2\theta }{2g}$
$\therefore \frac{H_1}{H_2}$ $=\frac{u^{2}si{n}^2\theta }{2g}\times \frac{2g}{u^{2}si{n}^2(90-\theta )}$
$=\frac{si{n}^2\theta }{co{s}^2\theta }$