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Standard XII

Physics

Partially Inelastic Collision

Two bodies ha...

Question

Two bodies having same mass $40 k g$ are moving in opposite directions, one with velocity of $10 m / s$ and the other with $7 m / s$ . If they collide and move as one body, the velocity of the combination is

10 m / s

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7 m / s

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3 m / s

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1.5 m / s

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Solution

The correct option is D $1.5 m / s$
Since there is no external force, momentum would remain conserved.
By the conservation of momentum:
$P_{i} = P_{f}$
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$
$40 \times 10 + (40) \times (- 7) = 80 \times v \Rightarrow v = 1.5 m / s$

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Two bodies having same mass 40kg are moving in opposite directions, one with velocity of 10m/s and the other with 7m/s. If they collide and move as one body, the velocity of the combination is

The correct option is D 1.5m/sSince there is no external force, momentum would remain conserved.By the conservation of momentum:Pi=Pfm1v1+m2v2=(m1+m2)v40×10+(40)×(−7)=80×v⇒v=1.5m/s

Two bodies having same mass $40 k g$ are moving in opposite directions, one with velocity of $10 m / s$ and the other with $7 m / s$ . If they collide and move as one body, the velocity of the combination is

The correct option is D $1.5 m / s$
Since there is no external force, momentum would remain conserved.
By the conservation of momentum:
$P_{i} = P_{f}$
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$
$40 \times 10 + (40) \times (- 7) = 80 \times v \Rightarrow v = 1.5 m / s$