Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is $(g = 9.8 m / s^{2})$

4.9 m/s²

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2.45 m/s²

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1.4 m/s²

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9.5 m/s²

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Solution

The correct option is C
1.4 m/s²

$A c c e l e r a t i o n = \frac{(m_{2} - m_{1})}{(m_{2} + m_{1})} g = \frac{4 - 3}{4 + 3} \times 9.8 = \frac{9.8}{7} = 1.4 m / s e c^{2}$

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Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is (g=9.8m/s2)

The correct option is C 1.4 m/s2 Acceleration=(m2−m1)(m2+m1)g=4−34+3×9.8=9.87=1.4 m/sec2

Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is $(g = 9.8 m / s^{2})$

The correct option is C
1.4 m/s²

$A c c e l e r a t i o n = \frac{(m_{2} - m_{1})}{(m_{2} + m_{1})} g = \frac{4 - 3}{4 + 3} \times 9.8 = \frac{9.8}{7} = 1.4 m / s e c^{2}$