Two bodies of masses 1 kg and 2 kg have equal momentum. Then, the ratio of their kinetic energies is

3: 1

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2 : 1

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1 : 1

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1 : 3

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Solution

The correct option is B
2 : 1

$m_{1} v_{1} = m_{2} v_{2}$

$\frac{v_{1}}{v_{2}} = \frac{m_{2}}{m_{1}} = \frac{2}{1}$

Ratio of their kinetic energy = $\frac{\frac{1}{2} m_{1} v_{1}^{2}}{\frac{1}{2} m_{1} v_{2}^{2}} = \frac{m_{1}}{m_{2}} {(\frac{2}{1})}^{2} = 2 : 1$

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