Two bodies of masses $1 k g$ and $2 k g$ have equal momentum. Then, the ratio of their kinetic energies is:

2 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $2 : 1$
The relation between kinetic energy and momentum is given by,

$K = \frac{1}{2} m v^{2} = \frac{p^{2}}{2 m}$ where $p$ is the momentum of body.

Hence, $\frac{K_{1}}{K_{2}} = \frac{m_{2}}{m_{1}}$ since momentum of the two bodies are same.

$\frac{K_{1}}{K_{2}} = \frac{m_{2}}{m_{1}} = 2$

Suggest Corrections

Similar questions

Two bodies of masses 1 kg and 2 kg have equal momentum. Then, the ratio of their kinetic energies is

3 k g

1 k g

m_{1}

m_{2}

m_{1} a n d m_{2}

A

B

3 : 1

1 : 3

Join BYJU'S Learning Program