Two bodies of masses 10 kg and 2 kg are moving with velocities 2 -7 -3 k- and -10 -35 -3 k- m - s respectively- The velocity of their centre of mass isA- 2 -2 k- m - sB- 2 -2 -2 k- m - sC- 2 - m - sD- 2 k- m - s

The correct option is D 2 k̂ m/sm_1 = 10 kg, m_2 = 2 kg v_i= 2 î 7 ĵ + 3 k̂ and v_2 = 10 î + 35 ĵ 3 k̂ ∴v_CM = m_1 v_1 + m_2 v_2m_1 + m_2 v_CM= 10(2 î 7 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Velocity of COM

Two bodies of...

Question

Two bodies of masses $10 kg$ and $2 kg$ are moving with velocities $2^i - 7^j + 3^k$ and $- 10^i + 35^j - 3^k m/s$ respectively. The velocity of their centre of mass is

2^i m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2^k m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2^j + 2^k) m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2^i + 2^j + 2^k) m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2^k m/s$
$m_{1} = 10 kg, m_{2} = 2 kg$
$_{i} = 2^i - 7^j + 3^k$ and $_{2} = - 10^i + 35^j - 3^k$
$∴ {\to v}_{C M} = \frac{m_{1}_{1} + m_{2}_{2}}{m_{1} + m_{2}}$
${\to v}_{C M} = \frac{10 (2^i - 7^j + 3^k) + 2 (- 10^i + 35^j - 3^k)}{10 + 2}$
${\to v}_{C M} = 2^k m/s$
Hence, the correct answer is option (b).

Suggest Corrections

Similar questions

Q. Two bodies of masses

10 k g

and

2 k g

are moving with velocities

2^i - 7^j + 3^k

and

- 10^i + 35^j - 3^k m / s

respectively. The velocity of the centre of mass of the two - body system is:-

Q. Two bodies of masses

10 k g

and

2 k g

are moving with velocities

(2^i - 7^j + 3^k) m / s

and

(- 10^i + 35 j - 3 k) m / s

respectively. Find the velocity of their centre of mass.

Q. Two bodies of mass 10 kg and 2 kg are moving with velocities

2^i - 7^j + 3^k m s^{- 1}

and

- 10^i + 35^j - 3^k m s^{- 1}

respectively. The velocity of their centre of mass is:

Q. A body of mass

3 k g

moving with a velocity

(2^i + 3^j + 2^k) m / s

collides with another body of mass

4 k g

with a velocity

(3^i + 2^j - 3^k) m / s

. The two bodies stick together after collision. The velocity of the composite body is

Q. A ball of mass

2 kg

, travelling with a velocity

2^i + 3^j + 4^k m/s

receives an impulse of

4^i + 2^j N-s

. What is the velocity of the ball immediately after the impulse is imparted?

Join BYJU'S Learning Program

Two bodies of masses 10 kg and 2 kg are moving with velocities 2^i−7^j+3^k and −10^i+35^j−3^k m/s respectively. The velocity of their centre of mass is

The correct option is B 2^k m/sm1=10 kg,m2=2 kg →vi=2^i−7^j+3^k and →v2=−10^i+35^j−3^k ∴→vCM=m1→v1+m2→v2m1+m2 →vCM=10(2^i−7^j+3^k)+2(−10^i+35^j−3^k)10+2 →vCM=2^k m/s Hence, the correct answer is option (b).

Two bodies of masses $10 kg$ and $2 kg$ are moving with velocities $2^i - 7^j + 3^k$ and $- 10^i + 35^j - 3^k m/s$ respectively. The velocity of their centre of mass is