Two bodies of masses $100 k g a n d 10000 k g$ are separated by distance of $1 m$ . The distance from the smaller body where the intensity of gravitational field is zero is

\frac{1}{9} m

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\frac{1}{10} m

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\frac{1}{11} m

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\frac{9}{11} m

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Solution

The correct option is C $\frac{1}{11} m$
$\frac{G \times 100}{x^{2}} = \frac{G \times 10000}{(1 - x)^{2}} \Rightarrow \frac{10}{x} = \frac{100}{1 - x} \Rightarrow x = \frac{1}{11} m$

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Two bodies of masses 100 kg and 10000 kg are separated by distance of 1m. The distance from the smaller body where the intensity of gravitational field is zero is

The correct option is C 111 mG×100x2=G×10000(1−x)2⇒10x=1001−x⇒x=111 m

Two bodies of masses $100 k g a n d 10000 k g$ are separated by distance of $1 m$ . The distance from the smaller body where the intensity of gravitational field is zero is

The correct option is C $\frac{1}{11} m$
$\frac{G \times 100}{x^{2}} = \frac{G \times 10000}{(1 - x)^{2}} \Rightarrow \frac{10}{x} = \frac{100}{1 - x} \Rightarrow x = \frac{1}{11} m$