Question

Two bodies of masses $15\text{kg}$ and $10\text{kg}$ are tied to the ends of massless string. The inextensible string passes over a frictionless pulley as shown. The acceleration of $15\text{kg}$ mass is

$($In terms of acceleration due to gravity $g)$

• A. $\frac{g}{6}$
• B. $\frac{g}{3}$
• C. $\frac{g}{4}$
• D. $\frac{g}{5}$

Answer 1

The correct option is D $\frac{g}{5}$


For $15\text{kg}$ block,

$15g–T=15a...\left(1\right)$

For $10\text{kg}$ block,

$T–10g=10a...\left(2\right)$

From $\left(1\right)$ and $\left(2\right)$,

$25a=5g$

$\Rightarrow a=\frac{g}{5}$